不能够按照我XSD中定义的NAME元素的类型显示,就是name的数据类型不符合我XSD中定义的条件,也会正常显示,总之达不到预期的XSD约束XML中显示数据类型的效果,各位兄弟帮帮忙>>>>
XSD文件定义 文件名称:shiporder1.xsd
<?xml version="1.0" encoding="ISO-8859-1"?>
<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema">
<xs:element name="shiporder">
<xs:complexType>
<xs:sequence>
<xs:element name="orderperson" type="xs:string" />
<xs:element name="shipto">
<xs:complexType>
<xs:sequence>
<xs:element name="name">
<xs:simpleType>
<xs:restriction base="xs:string">
<xs:pattern value="([a-z][A-Z])+"/>
</xs:restriction>
</xs:simpleType>
</xs:element>
<xs:element name="address" type="xs:string" />
<xs:element name="city" type="xs:string" />
<xs:element name="country" type="xs:string" />
</xs:sequence>
</xs:complexType>
</xs:element>
<xs:element name="item" maxOccurs="unbounded">
<xs:complexType>
<xs:sequence>
<xs:element name="title" type="xs:string" />
<xs:element name="note" type="xs:string" minOccurs="0" />
<xs:element name="quantity" type="xs:positiveInteger" />
<xs:element name="price" type="xs:integer" />
</xs:sequence>
</xs:complexType>
</xs:element>
</xs:sequence>
<xs:attribute name="orderid" type="xs:string" use="required" />
</xs:complexType>
</xs:element>
</xs:schema>
+++++++++++++++++++++++++++++++++
XML文件定义 文件名称:2007xs1.xml
<?xml version="1.0" encoding="ISO-8859-1"?>
<?xml-stylesheet type="text/xsl" href="newexample.xsl"?>
<shiporder orderid="889923"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:noNamespaceSchemaLocation="shiporder1.xsd">
<orderperson>John Smith</orderperson>
<shipto>
<name>oDkC</name>
<address>Langgt 23</address>
<city>4000 Stavanger</city>
<country>Norway</country>
</shipto>
<item>
<title>Empire Burlesque</title>
<note>Special Edition</note>
<quantity>1</quantity>
<price>10.90</price>
</item>
<item>
<title>Hide your heart</title>
<quantity>1</quantity>
<price>9.90</price>
</item>
</shiporder>
+++++++++++++++++++++++++++++
样式表定义 文件名称:newexample.xsl
<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/2001/XSL/Transform">
<xsl:template match="/">
<html>
<body>
<h2>new example</h2>
<table border="1">
<tr bgcolor="#9acd32">
<th>name</th>
<th>address</th>
<th>city</th>
<th>country</th>
</tr>
<xsl:for-each select="shiporder/shipto">
<tr>
<td><xsl:value-of select="name"/></td>
<td><xsl:value-of select="address"/></td>
<td><xsl:value-of select="city"/></td>
<td><xsl:value-of select="country"/></td>
</tr>
</xsl:for-each>
</table>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
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2007/10/14 1:27:00
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苏州大学关于一个XSD引用的问题[原创]
